Potentials of charge distribution

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SUMMARY

The discussion focuses on calculating the electric potential at the origin due to a uniformly distributed charge along a semicircle of radius R. The potential V is derived using the formula V = ∫ (k dq / r), where k is the Coulomb's constant and dq represents the differential charge element. The key insight is recognizing the symmetry of the charge distribution, which simplifies the integration process. By relating the charge density to the length with q = ρr and substituting dq = ρdr, one can effectively solve the integral to find the potential at the origin.

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  • Knowledge of calculus, specifically integration techniques
  • Concept of symmetry in physics problems
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  • Study the derivation of electric potential from charge distributions
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don23
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The question says that charges are distributed with uniform charge lambda along a semicircle of radius R, centered at the origin of a coordinate system. What is the potential at the origin?

I am not sure how to approach this one. Can anyone help me set this up and solve it? Thanks!
 
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Did you notice all dQ are at the same distance from O?
 
For questions in electrostatics, the general strategy is to look for symmetry. Once you have established some sort of symmetry, use it to your advantage. You know the differential form of the potential function

V = \int \frac{k dq}{r}
However from your geometric analysis, you only have r in your equation with no dr variable of integration. Instead you have a dq. You can relate the charge density to the length usually through something like

q=\rhor where \rho is the charge density, then
dq=\rhodr

Substituting this in, you will finally be able to solve the integral and get your answer. Give it a try.
 
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