Power and pressure of radiation. Is my answer correct?

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SUMMARY

The discussion centers on calculating the pressure and power of radiation using the equations derived from electromagnetic theory. The electric field (E) is given as 100 kV/m, leading to a magnetic field (B) calculation of approximately 0.0003335557 T. The intensity (I) is computed to be 26,543,519.23 W/m², resulting in a pressure of 0.08853742237 N/m². Additionally, the power calculation yields a value of 0.00000442687 W when factoring in the area of 0.5 mm².

PREREQUISITES
  • Understanding of electromagnetic theory, specifically the relationship between electric and magnetic fields.
  • Familiarity with the equations for intensity (I) and pressure (P) in the context of radiation.
  • Basic knowledge of unit conversions, particularly between different metric units.
  • Proficiency in algebraic manipulation of physical equations.
NEXT STEPS
  • Study the derivation of the intensity formula in electromagnetic waves.
  • Learn about the implications of pressure in radiation physics.
  • Explore the relationship between power, intensity, and area in electromagnetic contexts.
  • Investigate real-world applications of radiation pressure in engineering and physics.
USEFUL FOR

Students and professionals in physics, particularly those focusing on electromagnetism, as well as engineers working with radiation applications.

loki4000
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Homework Statement


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Homework Equations


E=100 kV/m E=cB
B = E/c B=(100000/2.998*10^8) B=0.0003335557
m = 10g = 0.01kg A=0.5mm^2 = 5*10^-7 m^2

I = (EB)/(4п*10^-7) = (100000)(0.0003335557) / (4п*10^-7)
I = 26543519.23

The Attempt at a Solution


a) Pressure = I/c = (26543519.23 )/(2.998*10^8)
Pressure = 0.08853742237 N/m^2
b)
Power = IA
a = Power/cm = IA/cm
a = (26543519.23 )(5*10^-7) / (2.998*10^8)(0.01)
a = 0.00000442687
 
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