Power concept related to gravity, constant speed, and air resistance

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Homework Help Overview

The problem involves an object weighing 100N moving vertically upward at a constant velocity of 5 m/s, specifically examining the concept of power in relation to gravity and the forces acting on the object.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between constant velocity and force, with one questioning whether constant velocity implies zero force and thus zero power. Others clarify the distinction between net force and applied power.

Discussion Status

The discussion is ongoing, with participants exploring the definitions of applied power versus net force. Clarifications have been offered regarding the interpretation of the question and the meaning of "power required."

Contextual Notes

Participants are navigating the implications of the problem's wording, particularly regarding the concept of "applied power" in the context of constant velocity and gravitational force.

Jmedz4nights
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Homework Statement


An object weighting 100N is traveling vertically upward from the Earth in the absence of air resistance at a constant velocity of 5 m/s. What is the power required to keep the object in motion?


Homework Equations


P = ΔE/t and P = Fvcosθ


The Attempt at a Solution



The explanation given in TPR(the princeton review book) is: since the object's velocity is upward and constant and the force necessary to propel the object is also upward and constant we may use the equation: P = Fv = 100N(5) = 500W.

What I don't understand is this: If the velocity is constant, then the force should be zero, and that should make the Power zero too, right?
 
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Hi Jmedz4nights! Welcome to PF! :smile:
Jmedz4nights said:
If the velocity is constant, then the force should be zero, and that should make the Power zero too, right?

If the velocity is constant, then the total force (net force) is zero …

so the total power is zero,

but that's non-zero applied power,

and equal and opposite non-zero gravitational power!

The question is only asking for the applied power. :wink:
 
Thank you tiny-tim! Where in the question stem do you infer applied power, though?
 
because it says …
Jmedz4nights said:
What is the power required to keep the object in motion?

… and "power required" obviously means the power we have to add :wink:
 
Thank you again all your help, tiny-tim.
 

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