Power dissipated in the inductor

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Homework Help Overview

The discussion revolves around an RL AC circuit involving a 60mH inductor and a 3kΩ resistor connected to an AC source. The original poster seeks to demonstrate that the power dissipated in the inductor is zero and is looking for ways to express this mathematically.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster calculates the current in the circuit and acknowledges the inductor's role but seeks clarification on how to express this with equations. Some participants suggest calculating power over one cycle using an integral approach, while others reference average power formulas involving RMS values and phase angles.

Discussion Status

The discussion is ongoing, with participants providing different approaches to calculating power in the circuit. There is a mix of suggestions regarding the mathematical methods to use, and the original poster expresses a need for simpler explanations due to their current level of understanding.

Contextual Notes

The original poster indicates a lack of familiarity with certain concepts, suggesting that there may be constraints related to their current coursework or understanding of the material.

noppawit
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In RL, AC circuit, an AC source vst = 220sin(40000t-45°) is connected to a 60mH inductor and a 3kΩ resistor.

Show that the power dissipated in the inductor is zero.



The current in this circuit is 0.057A as I calclulated. I know that inductor has no charging role in this circuit. But how can I write, describe this by equation?

Thank you.
 
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You need to find the power over one cycle, (or an integral number if you choose).

[tex]P = \int v(t)i(t)dt[/tex]
 
Would you please make it simpler? I have not learned this before. I learned that

[tex]P_{avg} = V_{rms}I_{rms}cos(\theta) = V_{rms}I_{rms}\frac{R}{Z}[/tex]

only.
 
You need to calculate both the current through, and the voltage across the inductor as a functions of time.

Inductors, being what they are, you should find that they are 90 degrees out of phase.

Since this is homework, you need to show some work. Generally, the more work the more help.
 

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