Power dissipated in variable resistor?

AI Thread Summary
The discussion centers on the behavior of power dissipation in a variable resistor, which initially increases and then decreases, likely due to the relationship between emf and internal resistance. It is noted that maximum power occurs at a specific loading resistance, highlighting the importance of impedance matching. Internal resistance is generally considered constant for theoretical calculations, although it may vary slightly in practical scenarios. The relationship between power, voltage, and current is emphasized, with the conclusion that power is lowest at both extremes of the variable resistor's range. Understanding these dynamics is crucial for optimizing circuit performance.
CAH
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See photo!

Why does the power dissipated increase and then decrease (see graph)? Is it something to do with emf?
Also can internal resistance change as the variable resistor increases/decreases or is it always constant?

- this isn't one of the questions they ask I'm just wondering
 

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CAH said:
See photo!

Why does the power dissipated increase and then decrease (see graph)? Is it something to do with emf?
Also can internal resistance change as the variable resistor increases/decreases or is it always constant?

- this isn't one of the questions they ask I'm just wondering

You can derive the power on the variable resistor in terms its resistance. Keep the emf and internal resistance constant.
It is a very important result that the power is maximum at a certain loading resistance - how is it related to the internal resistance of the source?
Have you heard about impedance matching?
 
Internal resistance can be assumed as being fixed for this exercise, though in practice it can be expected to change slightly.

Can you derive an expression for the power in Y, perhaps assume a particular value for r. Then sketch your graph, power versus value of Y.
 
I don't understand this still,

Py= VI
V= emf - rI
Py= (emf - Ir)I ...=0
 
What is the current in the circuit in therms of the emf and the resistors?
 
CAH said:
See photo!

Why does the power dissipated increase and then decrease (see graph)? Is it something to do with emf?
Also can internal resistance change as the variable resistor increases/decreases or is it always constant?

- this isn't one of the questions they ask I'm just wondering
to answer your question, the internal resisitance won't change with respect to the variable resistor
 
CAH said:
I don't understand this still,

Py= VI
V= emf - rI
Py= (emf - Ir)I ...=0
this is a good start. Your problem is you need to get rid I.

In your second equation, try to get rid of I using Y and r
 
CAH said:
See photo!

Why does the power dissipated increase and then decrease (see graph)? Is it something to do with emf?
Also can internal resistance change as the variable resistor increases/decreases or is it always constant?

-
 
Last edited:
Eliminate current from your equations and see what function you get relating the power with the load Y..Also see whether this power is total power or power consumed by load Y..
 
  • #10
Why does the power dissipated increase and then decrease (see graph)?

Power = voltage * current.

Consider two cases...

1) The variable resistor is set to a very high value (eg open circuit) => The current is very low or zero => Power is very low.
2) The variable resistor is set to a very low value (eg short circuit) => Voltage is very low or zero => Power is very low.

So at both ends of the range the power is very low. So no surprise it's higher in the middle.
 
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