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## Homework Statement

For the circuit shown below the 20-ohm resistor is immersed in water surrounded by insulating foam; the equivalent resistance through the circuit is 40 ohms. The current through it is 0.75A. What is the power dissipated through the 20 ohm resistor?

## Homework Equations

$$ P=I^2*R$$

## The Attempt at a Solution

$$ P=0.75^2*20$$

$$ P=11.25W$$

The solution to this problem gives 22.5W, why is the power dissipated through the resistor doubled here? Does the water or insulating foam affect the power at all? or is power calculated for the entire circuit?

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