(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Heater dissipates 500W when applied potential diference is 110V and wire is 800C. How much power would it dissipate if the wire temperature were held at 200C?

2. Relevant equations

a=4.0e-4

p=V^2/R

Rf=R0(1+a(T-T0) where R is resistance after temp change

R0 is initial resistance

a is coefficient of resistivity

3. The attempt at a solution

P=V^2/R

R=V^2/P

R=110^2/500

R=24.2

Rf=24.2(1+4.0e-4(200-800)

Rf=18.392

P=110^2/18.392

I'm sure it is just a silly mistake I have done somewhere only just started electronics today after a 2 month university break!

Answer should be 610W

Thanks for any help

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# Homework Help: Power dissipation due to temperature change

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