Power Dissipation: Understanding Equations & Solutions

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Homework Help Overview

The discussion revolves around power dissipation in the context of physics, specifically focusing on the equations related to power, force, and velocity. Participants are exploring the relationships between these variables and the implications of drag force in their calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the validity of different equations for power, particularly the substitution of force in the power equation. There is an exploration of how power relates to velocity and drag force, with attempts to derive relationships based on proportionality.

Discussion Status

Some participants have made progress in understanding the initial parts of the problem, while others are still grappling with the implications of their equations. Guidance has been offered regarding the need to carefully consider each factor in the drag formula, indicating a productive direction in the discussion.

Contextual Notes

There appears to be a focus on the proportional relationship between power and velocity, with specific attention to how changes in power affect velocity. Participants are also navigating through assumptions related to the drag coefficient and area in their calculations.

soupastupid
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Homework Statement





Homework Equations



P=F*V

The Attempt at a Solution



why isn't it

P = Cd(A^2)(v^2) * (v)

i don't see what i could do
 

Attachments

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soupastupid said:

Homework Equations



P=F*V
This is correct.

The Attempt at a Solution



why isn't it

P = Cd(A^2)(v^2) * (v)
But this is not. You made an error when you substituted for F in the power equation. Redo it, paying attention to each factor in the drag formula.
 
ok i figured out the first part

how do i figure out part B?

I kno the power is proportional to v^3
and so if i increase the power by 10%
i should get

??

if Pi = -(vi^3)AC_d

then 1.1Pi=-(vf^3)AC_d

Pi = (-(vf^3)AC_d ) / 1.1

(vf^3) = 1.1(vi^3)

then what?
 

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Solve for Vf in terms of Vi. (Take the cube root of both sides.)
 

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