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Power mechanics physics problem

  1. Jul 12, 2010 #1
    A 50kg student climbs a 5.0m long rope and stops at the top.What must her average speed be in order to match the power output of 200w.
    a)0.20m/s
    b)0.41m/s
    c)0.10m/s

    My Work :
    And stops at the top => v=0 and h=5m so I'll use mgh.
    Now power output = variation of energy/1

    But average means the variation of x /variation in time.

    Any help will be great,
    Thanks
     
  2. jcsd
  3. Jul 12, 2010 #2

    Doc Al

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    Staff: Mentor

    Re: Mechanics

    How much work does she have to do to climb the rope? In what time must she complete the climb to have her average power equal 200 W?
     
  4. Jul 12, 2010 #3
    Re: Mechanics

    Work = mgh , where h=5

    Power = Work/time

    time = Work / power

    Average speed = 5 / time(gotten) ?
     
  5. Jul 12, 2010 #4

    Doc Al

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    Staff: Mentor

    Re: Mechanics

    Sounds good to me.
     
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