Power mechanics physics problem

  • Thread starter -Aladdin-
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  • #1
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A 50kg student climbs a 5.0m long rope and stops at the top.What must her average speed be in order to match the power output of 200w.
a)0.20m/s
b)0.41m/s
c)0.10m/s

My Work :
And stops at the top => v=0 and h=5m so I'll use mgh.
Now power output = variation of energy/1

But average means the variation of x /variation in time.

Any help will be great,
Thanks
 

Answers and Replies

  • #2
Doc Al
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How much work does she have to do to climb the rope? In what time must she complete the climb to have her average power equal 200 W?
 
  • #3
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How much work does she have to do to climb the rope? In what time must she complete the climb to have her average power equal 200 W?

Work = mgh , where h=5

Power = Work/time

time = Work / power

Average speed = 5 / time(gotten) ?
 
  • #4
Doc Al
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Sounds good to me.
 

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