Power needed to keep car moving

  • Thread starter Thread starter VanKwisH
  • Start date Start date
  • Tags Tags
    Car Power
Click For Summary

Homework Help Overview

The discussion revolves around calculating the power required to maintain a car's speed of 80 km/h after it has slowed down from 90 km/h to 70 km/h. The subject area includes concepts of physics related to power, work, and force.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between power, work, and force, with one suggesting the use of acceleration to find force. Others express confusion regarding variable definitions and units of measurement, particularly concerning horsepower and its conversion to watts.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the variables involved and seeking clarification on the definitions of terms. Some guidance on the relationship between work and power has been provided, but no consensus or resolution has been reached.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a noted confusion regarding variable notation and units of measurement.

VanKwisH
Messages
107
Reaction score
0

Homework Statement


A 1200 kg car slows down from 90km/h to 70 km/h in about 5.0s on the level when it is in neutral. Approximately what power ( in watt's and hp ) is needed to keep the car traveling at a constant 80km/h?


Homework Equations


P = W / t


The Attempt at a Solution


I really have no idea ... and
how much does 1hp = in watts and in joules ?
550 ft lbs/s = in joules and watts?
 
Physics news on Phys.org
P=\frac{dW}{dt}=\frac{d}{dt}(Fs)=F\frac{ds}{dt}=Fvif you have the change in velocity and the time it acts for...you can find acceleration and F=ma...so you can find the power
 
what does each of ur variables mean?? cause i think i use a different variables than u do and i find it confusing to understand
 
Oh well from the definition of power, the rate at which work,W, is done =\frac{dW}{dt} since work done= Force(F)*distance(s) i.e.\frac{dW}{dt}=\frac{d}{dt}(Fs) since force is constant you can then re-write it like \frac{d}{dt}(Fs)=F\frac{ds}{dt} and well v=\frac{ds}{dt}

In short: F=Force of car
P=power
v=velocity of car
 
wha ? so the answer is?
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
15
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K