Power of a Source: Calculating Intensity & Power

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SUMMARY

The discussion centers on calculating the power radiated by a loudspeaker with a circular opening of 20 cm diameter, emitting sound waves with an intensity of 0.2 milli watts/m². The user correctly applies the formula for intensity, I = P/A, where the area A is calculated using the formula A = πR², resulting in an area of 0.0314 m². The final calculation yields a power output of 6.28 x 10^(-6) watts, confirming the user's solution as accurate.

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  • Familiarity with the formula for area of a circle
  • Basic knowledge of units of measurement in physics
  • Ability to perform calculations involving π (pi)
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Physics students, audio engineers, and anyone interested in the principles of sound wave behavior and power calculations.

Amith2006
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Sir,
A loud speaker having a circular opening of diameter 20 cm is emitting sound waves uniformly. The intensity of sound at the opening is 0.2 milli watt/m^2. What is the power radiated by the source?
I solved it in the following way:
Intensity = power/Area
Here Area = (pi)R^2
= 3.14 x 0.01
= 0.0314 m^2
Power = 0.2 x 0.0314 milli watts
= 6.28 x 10^(-6) watts
Is it right?
 
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Looks correct to me. Did you think it was too easy?
 

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