What Is the Power Developed by a Boat Overcoming Drag?

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SUMMARY

The power developed by a boat overcoming drag is calculated using the formula Fv, where F represents the total frictional drag experienced by the boat. The incorrect option, 1/2Fv, arises from a misunderstanding of the relationship between drag and the force required to maintain constant speed. The boat must exert a force equal to the total drag F to sustain its velocity v, leading to the conclusion that the correct answer is Fv. This discussion clarifies the fundamental principles of fluid dynamics relevant to the problem.

PREREQUISITES
  • Understanding of basic physics concepts, particularly force and power
  • Familiarity with fluid dynamics principles
  • Knowledge of the relationship between work, force, and velocity
  • Basic mathematical skills for integrating forces
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  • Study the principles of fluid dynamics in relation to drag forces
  • Learn about the mathematical derivation of power in physics
  • Explore the concept of resistance in fluid flow and its implications
  • Investigate real-world applications of drag force in marine engineering
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Students of physics, marine engineers, and anyone interested in understanding the dynamics of boats and fluid resistance will benefit from this discussion.

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Homework Statement


A boat moving at constant speed v through still water experiences a total frictional drag F.
What is the power developed by the boat?
a) 1/2Fv b) Fv

The Attempt at a Solution


I know the correct answer is b. My confusion is why is a incorrect?
My reasoning: The boat experiences a total drag of F. Which means at every point the boat experiences a resistance where R < F. Thus to steer at v, we have to apply a force of R. Which will provide the only option 1/2Fv.
 
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What exactly happens at every point between the boat and the water is a big story of fluid dynamics I doubt we want to discuss for this specific problem. There will be an infinitesimal force ##dF_i## at every point and the sum(more accurately the integral) of all these forces will be ##\vec{F}+\vec{A}=\sum \vec{dF_i}## , where A is the buoyancy force which is canceled by the weight of the boat. So all that is left is the force F. So we have to supply a force equal and opposite to F to keep the boat move at constant speed v. If you do the math (starting from the definition of the power and also using the definition of work of a force) for a constant force applied at a body that moves with constant velocity v, the power provided by force F is equal to Fv.
 
Last edited:
Faiq said:
I know the correct answer is b. My confusion is why is a incorrect?
My reasoning: The boat experiences a total drag of F. Which means at every point the boat experiences a resistance where R = F. Thus to steer at v, we have to apply a force of R. Which will provide the only option 1/2Fv.
Drag and resistance are the same thing!
 

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