Power of Elevator Motor: 500kg Acceleration & Cruising Speed

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Homework Help Overview

The problem involves a 500 kg elevator that accelerates upward for 3.50 seconds until it reaches a cruising speed of 1.75 m/s. The discussion focuses on calculating the average power of the elevator motor during this acceleration phase and comparing it to the power at cruising speed.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of acceleration and distance traveled during the elevator's upward movement. There are attempts to derive tension and power, with some participants questioning the correctness of units and the relevance of distance in the context of the problem.

Discussion Status

Multiple interpretations of the calculations are being explored, with some participants providing feedback on the original poster's approach. There is an ongoing examination of the relationship between force and power, as well as the implications of calculating average power versus instantaneous power.

Contextual Notes

Participants note potential misunderstandings regarding the units of measurement and the specific requirements of the problem. There is an emphasis on ensuring that calculations align with the definitions of power and force.

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Homework Statement


A 500 kg elevator starts from rest. It moves upward for 3.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s.
(a) What is the average power of the elevator motor during this period?
(b) How does this power compare with the motor power when the elevator moves at its cruising speed?
Pcruising = ?

Homework Equations


F=ma
P=W/deltaT
W=Fdelta(r)cos(theta)

The Attempt at a Solution


This problem, I first found the acceleration using Vf= Vi +at
a= 0.5m/s^2

Next I plugged this into delta x = volt +1/2a(t^2) and found delta x to be 3.0625
Next, I solved for tension using: T-Mg = Ma
T= M(a+g) = 10,578.75 W
Is this correct? If it isn't, can someone explain to me how to approach this problem?
 
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Geminiforce said:

Homework Statement


A 500 kg elevator starts from rest. It moves upward for 3.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s.
(a) What is the average power of the elevator motor during this period?
(b) How does this power compare with the motor power when the elevator moves at its cruising speed?
Pcruising = ?

Homework Equations


F=ma
P=W/deltaT
W=Fdelta(r)cos(theta)

The Attempt at a Solution


This problem, I first found the acceleration using Vf= Vi +at
a= 0.5m/s^2

Next I plugged this into delta x = volt +1/2a(t^2) and found delta x to be 3.0625
Next, I solved for tension using: T-Mg = Ma
Your method looks good up until this point:
Geminiforce said:
T= M(a+g) = 10,578.75 W
Perhaps this is a typo but, tension is a force and not power.
 
Geminiforce said:

Homework Statement


A 500 kg elevator starts from rest. It moves upward for 3.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s.
(a) What is the average power of the elevator motor during this period?
(b) How does this power compare with the motor power when the elevator moves at its cruising speed?
Pcruising = ?

Homework Equations


F=ma
P=W/deltaT
W=Fdelta(r)cos(theta)

The Attempt at a Solution


This problem, I first found the acceleration using Vf= Vi +at
a= 0.5m/s^2

Next I plugged this into delta x = volt +1/2a(t^2) and found delta x to be 3.0625
Why? The problem did not ask for distance moved.

Next, I solved for tension using: T-Mg = Ma
T= M(a+g) = 10,578.75 W
No, the units are wrong. kg (m/s2 is Newtons, not Watts. This is a force not power. Do you know how to convert from force to power, i.e. from Newtons to Watts?

Is this correct? If it isn't, can someone explain to me how to approach this problem?
 
HallsofIvy said:
Why? The problem did not ask for distance moved.


No, the units are wrong. kg (m/s2 is Newtons, not Watts. This is a force not power. Do you know how to convert from force to power, i.e. from Newtons to Watts?

You're right i accidently put the force in the wrong units...
I meant to put Power=M(a+g)(v)... However the question asks for the average power and I think the power calculated there is the power at 3 second. Would this power i just calculated be the cruising speed?
 

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