Power of Elevator Motor: 500kg Acceleration & Cruising Speed

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AI Thread Summary
The discussion centers on calculating the average power of a 500 kg elevator motor during its acceleration phase and comparing it to the power at cruising speed. The user initially determines the acceleration and distance traveled but faces confusion regarding the units of power and force. It is clarified that tension is a force measured in Newtons, not Watts, and the correct conversion from force to power involves incorporating velocity. The user acknowledges a mistake in unit conversion and questions whether the calculated power reflects cruising speed. The conversation emphasizes the importance of understanding the relationship between force, power, and velocity in physics problems.
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Homework Statement


A 500 kg elevator starts from rest. It moves upward for 3.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s.
(a) What is the average power of the elevator motor during this period?
(b) How does this power compare with the motor power when the elevator moves at its cruising speed?
Pcruising = ?

Homework Equations


F=ma
P=W/deltaT
W=Fdelta(r)cos(theta)

The Attempt at a Solution


This problem, I first found the acceleration using Vf= Vi +at
a= 0.5m/s^2

Next I plugged this into delta x = Vot +1/2a(t^2) and found delta x to be 3.0625
Next, I solved for tension using: T-Mg = Ma
T= M(a+g) = 10,578.75 W
Is this correct? If it isn't, can someone explain to me how to approach this problem?
 
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Geminiforce said:

Homework Statement


A 500 kg elevator starts from rest. It moves upward for 3.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s.
(a) What is the average power of the elevator motor during this period?
(b) How does this power compare with the motor power when the elevator moves at its cruising speed?
Pcruising = ?

Homework Equations


F=ma
P=W/deltaT
W=Fdelta(r)cos(theta)

The Attempt at a Solution


This problem, I first found the acceleration using Vf= Vi +at
a= 0.5m/s^2

Next I plugged this into delta x = Vot +1/2a(t^2) and found delta x to be 3.0625
Next, I solved for tension using: T-Mg = Ma
Your method looks good up until this point:
Geminiforce said:
T= M(a+g) = 10,578.75 W
Perhaps this is a typo but, tension is a force and not power.
 
Geminiforce said:

Homework Statement


A 500 kg elevator starts from rest. It moves upward for 3.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s.
(a) What is the average power of the elevator motor during this period?
(b) How does this power compare with the motor power when the elevator moves at its cruising speed?
Pcruising = ?

Homework Equations


F=ma
P=W/deltaT
W=Fdelta(r)cos(theta)

The Attempt at a Solution


This problem, I first found the acceleration using Vf= Vi +at
a= 0.5m/s^2

Next I plugged this into delta x = Vot +1/2a(t^2) and found delta x to be 3.0625
Why? The problem did not ask for distance moved.

Next, I solved for tension using: T-Mg = Ma
T= M(a+g) = 10,578.75 W
No, the units are wrong. kg (m/s2 is Newtons, not Watts. This is a force not power. Do you know how to convert from force to power, i.e. from Newtons to Watts?

Is this correct? If it isn't, can someone explain to me how to approach this problem?
 
HallsofIvy said:
Why? The problem did not ask for distance moved.


No, the units are wrong. kg (m/s2 is Newtons, not Watts. This is a force not power. Do you know how to convert from force to power, i.e. from Newtons to Watts?

You're right i accidently put the force in the wrong units...
I meant to put Power=M(a+g)(v)... However the question asks for the average power and I think the power calculated there is the power at 3 second. Would this power i just calculated be the cruising speed?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

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