# I Power series Construction Help

Tags:
1. Mar 8, 2016

### Euler2718

Very basic issue here.

Using:

$$\frac{1}{1-x} = \sum_{i=0}^{\infty} x^{i} , |x|<0$$

Find the power series representation and interval of convergence for:

$$f(x) = \frac{1}{(1-3x)^{2}}$$

We have that:

$$\frac{d}{dx}\left[\frac{1}{1-x}\right] = \frac{1}{(1-x)^{2}} = \sum_{i=0}^{\infty} ix^{i-1} , |x| < 0$$

Of all things, the algebra of manipulating the function in question is stumping me. For some reason whatever I try doesn't seem to work.

2. Mar 8, 2016

### Staff: Mentor

Do you understand what they're doing here? Particularly in getting the summation at the end? This is basically the same as what you need to do with your series.

Also your inequality at the end is wrong. $|x| \ge 0$ for all real x.

3. Mar 10, 2016

### Math_QED

If I am correct the series converges for all x: |x|<1. When you find the derivative of this series, it can be that the series converges in either -1 and or 1, so you might want to check that.

4. Mar 13, 2016

### Ssnow

yes, the initial series converges for $|x|<1$. Observe that in the second case $x$ will be replaced by $3x$, you must consider that ...