Power Series Representation of e^(sin(x))

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SUMMARY

The power series representation of the function f(x) = e^(sin(x)) can be derived using the Taylor series expansion for e^x and the series expansion for sin(x). The correct formulation is e^(sin(x)) = ∑ (sin(x))^n/n!, where n ranges from 0 to infinity. To find the nth term of the series, one must simplify the expression ∑_{r=0}^{∞} (1/r!) (∑_{t=0}^{∞} (-1)^t x^(2t+1)/(2t+1)!)^r, which involves combining the series for sin(x) into the exponential series.

PREREQUISITES
  • Understanding of Taylor series expansions
  • Familiarity with the exponential function e^x
  • Knowledge of the sine function series expansion
  • Basic skills in manipulating infinite series
NEXT STEPS
  • Study the Taylor series for e^x in detail
  • Learn how to derive the series expansion for sin(x)
  • Explore techniques for simplifying nested series
  • Investigate convergence criteria for power series
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Students preparing for calculus exams, mathematicians interested in series expansions, and educators teaching advanced calculus concepts.

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Homework Statement



Find the power series representation of the following:

f(x) = e^(sin(x))

Homework Equations



I know this to be true:

e^x = (Inf Sum, n=0) (x^n/n!)

The Attempt at a Solution



So, in substituting sin(x) for x, I get:

e^(sin(x)) = 1 + sin(x)/1 + sin(x)/2 + sin(x)/6 + ...

or

e^(sin(x)) = (Inf Sum, n=0) ((sin(x))^n/n!)

Not sure where I'm going wrong here, so a nudge in the right direction would be greatly appreciated. Thanks in advance!
 
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Does anyone have any advice here? I have an exam tomorrow, for which I am almost fully prepared. With my luck though, this problem will be on the exam and I'll be screwed!

Any help would be much appreciated!
 
Also, by (Inf Sum, n=0), I meant \sum

Thanks
 
I think everybody knows what you mean. You presented the problem pretty clearly. But I don't know how to express the nth term of your series in any nice closed form. If nobody answered they probably don't either. It's pretty easy to find the first few terms by expanding sin(x) as a series. But I don't know the general term.
 
In short, we have to simplify this:

\sum_{r=0}^{\infty}\frac{1}{r!}(\sum_{t=0}^{\infty} \ \frac{(-1)^tx^{2t+1}}{(2t+1)!})^r

That looks pretty horrendous to begin with.
 
Maybe that IS the answer...
 
Except, incorporate the 'r' as t's
 

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