PreCalc Functions Help: Translations

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SUMMARY

The discussion focuses on the translation of functions in precalculus, specifically how to determine the new coordinates of a point after a translation. The original point (0, -1/2) on the graph of function f is translated using the formula g(x) = f(x + 1/2) + 2. The correct new coordinates after applying the translation are (-1/2, 3/2), correcting the user's initial answer of (-1/2, 2).

PREREQUISITES
  • Understanding of function translations in precalculus
  • Familiarity with coordinate geometry
  • Knowledge of the translation formula f(x-h) + k
  • Ability to manipulate algebraic expressions
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  • Study the concept of function transformations in precalculus
  • Learn how to apply the translation formula f(x-h) + k in various contexts
  • Explore examples of translating different types of functions
  • Practice problems involving translations of points on graphs
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Students studying precalculus, educators teaching function transformations, and anyone seeking to improve their understanding of graph translations in mathematics.

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Q: The point (0,-1/2) is on the graph of f. If g is a translation of f so that g(x)=f(x+1/2) + 2, then what are the coordinates of the translated point?

I got the answer (-1/2, 2) but I'm not sure if that is the correct answer.
Thanks!
 
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Re: PreCalc Functions Help

The translation:

$$f(x-h)+k$$

takes the point $(x,y)$ on $f$, and moves it to $(x+h,y+k)$.

You have the correct new $x$-coordinate, but not the correct new $y$-coordinate.
 

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