MHB PreCalc Functions Help: Translations

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The point (0, -1/2) on the graph of function f translates to g(x) = f(x + 1/2) + 2. The translation formula indicates that the new coordinates are determined by the shifts in the x and y directions. The correct new x-coordinate is -1/2, but the new y-coordinate needs adjustment. The final coordinates of the translated point are (-1/2, 3/2).
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Q: The point (0,-1/2) is on the graph of f. If g is a translation of f so that g(x)=f(x+1/2) + 2, then what are the coordinates of the translated point?

I got the answer (-1/2, 2) but I'm not sure if that is the correct answer.
Thanks!
 
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Re: PreCalc Functions Help

The translation:

$$f(x-h)+k$$

takes the point $(x,y)$ on $f$, and moves it to $(x+h,y+k)$.

You have the correct new $x$-coordinate, but not the correct new $y$-coordinate.
 

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