The forum discussion centers on solving a precalculus trigonometry problem regarding arc length, specifically question #7 from the Alberta Education math release document. The equation used is a = theta * r, where theta is the angle in radians and r is the radius. The initial calculation of a = (5pi/6) * 20 was incorrect, as the total perimeter also includes additional lengths. The correct approach involves adding the arc length to the straight segments, resulting in a final formula of [(5pi/6)*20] + 16(2) + [(5pi/6)*4].
PREREQUISITESStudents studying precalculus, educators teaching trigonometry concepts, and anyone preparing for standardized math assessments.
I think 'total perimeter' here means you go entirely around the area which is swept out by the wiper.A123 said:Homework Statement
http://education.Alberta.ca/media/9451970/07_math30-1_released_2014-15.pdf
question #7
Homework Equations
a=theta*r
The Attempt at a Solution
I did a=(5pi/6)*20 but the answer is not A
I agree with SteamKing's appraisal.SteamKing said:I think 'total perimeter' here means you go entirely around the area which is swept out by the wiper.
SteamKing said:I think 'total perimeter' here means you go entirely around the area which is swept out by the wiper.