- #1

Cal124

- 28

- 0

lim(x->2) (4x

^{2}+2)=18

skipping the introduction part

any advice? I am just not sure how to get rid of the

^{2}value to re-arrange |(4x

^{2}+2)-18| to look like |x-2|

|x-2|<delta |(4x

^{2}+2)-18|<epsilon

|(4x

^{2}-16|<epsilon

I did go down the route of

|(4x

^{2}+2)-18| = |2x+4| |2x-4|<epsilon

but this step just lead me to the same problem