Pressure applied to the ground by a man standing on stilts

[sebastian281172]

Homework Statement

How much pressure is applied to the ground by a 52 kg man who is standing on square stilts that measure 0.06 m on each edge?

Relevant Equations

p=(F/A)

Homework Statement: How much pressure is applied to the ground by a 52 kg man who is standing on square stilts that measure 0.06 m on each edge?
Homework Equations: p=(F/A)

P = (F/A)
= (52*9.81)/(.06^2)
= 207100

 

[mjc123]

How many stilts is he using?

 

[sebastian281172]

it doesn't matter because of it all factors back to the equation on top.

Ex. ((ab)/2 + (ab)/2)/c

= (2ab/2)/c
= ab/c

 

[mjc123]

Pressure is an intensive variable. You don't add the pressures. Forces are additive, pressures are not. The total force is mg, the total area is 2*0.06².

<< Solution deleted by a Mentor >>

 

[sebastian281172]

ohh thanks, i didn't know that

 

[PeroK]

Homework Statement: How much pressure is applied to the ground by a 52 kg man who is standing on square stilts that measure 0.06 m on each edge?
Homework Equations: p=(F/A)

P = (F/A)
= (52*9.81)/(.06^2)
= 207100

There are normally two stilts, are there not? The stilts themselves must weigh something.

 

[CardiniPanini]

There are normally two stilts, are there not? The stilts themselves must weigh something.

I'd think that if it asks for what pressure the man is applying to the ground, the stilts are probably treated as negligible to the solution.

 

[PeroK]

I'd think that if it asks for what pressure the man is applying to the ground, the stilts are probably treated as negligible to the solution.

Which is a dubious assumption, IMO. Unless you specify ultra lightweight stilts, perhaps.