Primary cause of the force induced by a current in a magnetic field.

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SUMMARY

The primary cause of the force experienced by a current-carrying rod in a magnetic field is due to the interaction between the magnetic field generated by the current and the external magnetic field. When current flows through the rod, moving charges create a magnetic field according to the right-hand grip rule. This induced magnetic field interacts with the external magnetic field, resulting in a net magnetic field that causes the rod to experience a force perpendicular to both the current and the external magnetic field, as described by the Lorentz force equation F=QvB.

PREREQUISITES
  • Understanding of Lorentz force and its application (F=QvB)
  • Knowledge of magnetic fields generated by electric currents
  • Familiarity with the right-hand grip rule for magnetic fields
  • Basic principles of electromagnetism
NEXT STEPS
  • Study the right-hand slap rule for determining force direction on current-carrying conductors
  • Explore the concept of magnetic field superposition in electromagnetism
  • Learn about the applications of the Lorentz force in electric motors
  • Investigate the relationship between current, magnetic fields, and forces in different configurations
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in understanding the principles of electromagnetism and the behavior of current-carrying conductors in magnetic fields.

qazadex
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Not sure if this is in the right section, but anyway...

Homework Statement


Explain the primary cause of the force experienced by the rod. In your explanation you must
refer to the magnetic field generated by the current.

The rod is carrying current perpendicular to the magnetic field created by two magnets.

Homework Equations



F=QvB, F=BIL

The Attempt at a Solution


So the first thing that came to mind was using one of the aforementioned equations as an explanation, saying that since the current is perpendicular to the magnetic field and therefore a force would be produced. However, the answer is as follows:

Owing to the moving charges of the current in the conducting rod, a magnetic field is
generated in accordance with the right-hand grip rule. This magnetic field then superimposes
onto the external magnetic field, resulting in a net magnetic field that has a varying intensity.
The conductor then experiences a force in the direction of the weaker region of the field and
the direction is given by the right-hand slap rule.

I can't wrap my head around this. How does the induced magnetic field interact with the external magnetic field to create a net magnetic field perpendicular to the direction of the external magnetic field? Since the magnetic fields are vectors, surely if a wire did not have an upwards or downwards force on it, how does a magnetic field acting on a wire in equilibirum have an effect perpendicular to it?

Sorry if this was confusing, and thanks for any answers.
 
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Well, I think you are right:
the magnetic field acts with a force F=QvxB on a moving charged particle.
Current means moving particles, so there is force on a current carrying wire. You can derive how the force can be expressed in terms of current and length of the wire.
http://en.wikipedia.org/wiki/Lorentz_force#Force_on_a_current-carrying_wire

Moving charged particles produce magnetic field and a current produces magnetic field around the wire. The resultant magnetic field around the wire is the sum of the external field and that generated by the current, but the current is not affected by its own magnetic field. Just like the electric field of a charge does not act on the charge itself.

ehild
 
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