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Prime Factorization Homework Problem 2

  1. Oct 18, 2009 #1
    1. The problem statement, all variables and given/known data
    Presidential elections are held every four years. Senators are elected every 6 years. If a senator was elected in the presidential election year of 2000, in what year would he or she campaign again during a presidential election year?



    2. Relevant equations
    dont know how I would show the answer using factorization

    2000+6=2006 2000+4=2004+4=2008

    3. The attempt at a solution
    2008
     
  2. jcsd
  3. Oct 18, 2009 #2

    symbolipoint

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    We need more information on this one. Anyway, try making a table of values starting with year 2000. Again, this seems to be a lowest common factor problem. There is a 4 and a 6, so .... ? ....!
     
  4. Oct 18, 2009 #3
    This was all the information I was provided for that question. Do I have the correct answer?
     
  5. Oct 18, 2009 #4
    Ok, same caveat (not very good at math), but here's what I think:

    2012.

    Here's how I arrived at that.

    i) Forget the 2000s, they are just confusing. Since it starts at 0, just focus on the 4 and the 6. A president gets elected every 4 years & a senator every 6 years.

    ii) Find the lowest (least?) common multiple of 4 and 6 by prime factoring each one.

    4 = 2 * 2​
    6 = 3 * 2​

    iii) Since there are 2s in both groups, circle the largest grouping of 2s (4 = 2*2) and not the other one.

    iv) Multiply all the circled prime factors (2*2*3) and you get 12.

    v) Draw a chart to check the answer.
     
  6. Oct 18, 2009 #5
    Look for their lowest common multiple. And that number is 12.

    2000 + 12 = the year 2012
     
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