Principle of conservation of linear momentum equation

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SUMMARY

The discussion focuses on applying the principle of conservation of linear momentum to a collision involving two blocks of mass 2kg each, where one block is initially at rest and the other moves at 8m/s. The spring constant is given as 16 N/m, and the resulting motion of the blocks is described using the equation x(t) = 2 * sin(2t). The participants confirm the correctness of the initial steps taken to derive the motion and discuss how to find maximum positions for oscillation using the derived equations.

PREREQUISITES
  • Understanding of conservation of linear momentum
  • Knowledge of simple harmonic motion (SHM)
  • Familiarity with spring constant and Hooke's Law (F = kx)
  • Ability to differentiate functions to find velocity and acceleration
NEXT STEPS
  • Learn how to derive equations of motion for simple harmonic oscillators
  • Study the relationship between angular velocity and linear velocity in SHM
  • Explore the concept of maximum displacement and speed in oscillatory motion
  • Investigate the effects of varying spring constants on oscillation frequency
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators looking for practical examples of momentum conservation and SHM applications.

SirPlus
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Homework Statement



A massless spring attached to a wall lies on a frictionless table. It has a block of mass 2kg attached to one end, initially the block is at rest. Another block, also of mass 2kg is sliding on the table top with a speed 8m/s. At t = o the moving block collides with the block on the spring . The two stick together and oscillate back and forth. If the spring constant is 16 n/m, find an expression x(t) which describes the motion of the blocks that are stuck together.


Homework Equations


-Principle of conservation of linear momentum equation



The Attempt at a Solution



Step 1:
I applied principle of conservation of linear momentum to the system to find the velocity after the collision.

Step 2:
I obtained the angular velocity with the data provided

Step 3:
I associated the harmonic motion of the system to that of a sin function - the rest/equilibrium postion equals zero

Step 4: I don't know how to obtain the maximum positions for the oscillation -

In my attempt the position at any time of the SHM is x(t) = 2 * sin2t

Please correct me if i am wrong ...
 
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I don't remember the formulae, but use F=kx for the spring. Use F=ma (so basically kx=ma) Acceleration in SHM is opposite to the direction of travel Using that, you'll get an euqation for your SHM.

The first 3 points are correct. The point of impact of the two blocks is the equilibrium position.
 
SirPlus said:

Homework Statement



A massless spring attached to a wall lies on a frictionless table. It has a block of mass 2kg attached to one end, initially the block is at rest. Another block, also of mass 2kg is sliding on the table top with a speed 8m/s. At t = o the moving block collides with the block on the spring . The two stick together and oscillate back and forth. If the spring constant is 16 n/m, find an expression x(t) which describes the motion of the blocks that are stuck together.


Homework Equations


-Principle of conservation of linear momentum equation



The Attempt at a Solution



Step 1:
I applied principle of conservation of linear momentum to the system to find the velocity after the collision.

Step 2:
I obtained the angular velocity with the data provided

Step 3:
I associated the harmonic motion of the system to that of a sin function - the rest/equilibrium postion equals zero

Step 4: I don't know how to obtain the maximum positions for the oscillation -

But you know the maximum speed...


SirPlus said:
In my attempt the position at any time of the SHM is x(t) = 2 * sin2t

Please correct me if i am wrong ...

How did you get it? And how did you define x? In what direction is it positive? In what units is it written?
(If you specify the direction and units, it is correct)

ehild
 
I obtained the maximum speed using the principle of conservation of linear momentum, i took the first derivative of the postion function with respect to time and equated the initial velocity at time zero - i then was able to determine the maximum displacement. Direction positive is along the positive x - axis(to the right).

I just needed you to verify whether my approache is OK
 
Last edited:

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