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Probability - Breaking up an event into unions of complements

  1. Mar 15, 2010 #1
    Why is it that given 3 events, A, B, and C describe a sample space, then:

    P(A) = P(ABCCC) + P(ABC)

    Shouldn't it be:

    P(A) = P(ABC) + P(ABCC) +P(ABCC) +P(ABCCC)

    Thanks!
     
  2. jcsd
  3. Mar 15, 2010 #2

    tiny-tim

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    Hi IniquiTrance! :smile:

    Yes.
     
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