Probability - Breaking up an event into unions of complements

  • Thread starter IniquiTrance
  • Start date
  • Tags
    Probability
  • #1
190
0
Why is it that given 3 events, A, B, and C describe a sample space, then:

P(A) = P(ABCCC) + P(ABC)

Shouldn't it be:

P(A) = P(ABC) + P(ABCC) +P(ABCC) +P(ABCCC)

Thanks!
 
  • #2
Hi IniquiTrance! :smile:

Yes.
 

Suggested for: Probability - Breaking up an event into unions of complements

Replies
31
Views
744
Replies
6
Views
921
Replies
3
Views
797
Replies
4
Views
846
Replies
4
Views
811
Replies
4
Views
815
Back
Top