Probability density from Wave Function

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SUMMARY

The probability density of finding a particle in space is given by the product of the wave function and its complex conjugate, represented as \(\Psi \Psi^* = |\Psi|^2\). This is distinct from simply squaring the wave function, \(\Psi^2\), which does not yield the correct probability density due to the presence of complex components. While certain eigenstates of atomic or molecular Hamiltonians can be real, making \(\Psi^2\) valid in those specific cases, the general rule remains that the probability density is defined by \(|\Psi|^2\).

PREREQUISITES
  • Understanding of wave functions in quantum mechanics
  • Knowledge of complex numbers and their properties
  • Familiarity with quantum mechanics terminology, particularly eigenstates and Hamiltonians
  • Basic grasp of probability density concepts
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  • Study the mathematical properties of complex conjugates in quantum mechanics
  • Explore the concept of eigenstates and their significance in quantum systems
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  • Investigate the implications of probability density in quantum mechanics
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Mandelbroth
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A friend of mine recently tried to tell me that the square of the wave function for a particle (that is, [itex]\Psi^2[/itex]) gives the probability density of finding a particle in space.

I disagree. I always thought that the wave function multiplied by its complex conjugate (that is, [itex]\Psi \Psi^*[/itex]) yielded the probability density for the particle. They are definitely not the same, because [itex]\forall a,b \neq 0, \ (a+bi)^2 = a^2 + 2abi + b^2 \neq a^2 + b^2[/itex].

So, is the probability density given by [itex]\Psi^2[/itex] or [itex]\Psi \Psi^* = |\Psi|^2[/itex]?
 
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Mandelbroth said:
A friend of mine recently tried to tell me that the square of the wave function for a particle (that is, [itex]\Psi^2[/itex]) gives the probability density of finding a particle in space.

I disagree. I always thought that the wave function multiplied by its complex conjugate (that is, [itex]\Psi \Psi^*[/itex]) yielded the probability density for the particle. They are definitely not the same, because [itex]\forall a,b \neq 0, \ (a+bi)^2 = a^2 + 2abi + b^2 \neq a^2 + b^2[/itex].

So, is the probability density given by [itex]\Psi^2[/itex] or [itex]\Psi \Psi^* = |\Psi|^2[/itex]?

It's the [itex]|\Psi|^2[/itex], a real number
 
Perhaps your friend referred to wave function that is eigenstate of some atomic or molecular Hamiltonian. These can be chosen to be real, so then ##\Psi^2## gives the correct density as well as ##|\Psi|^2##. But the latter is the general expression.
 

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