- #1

Mandelbroth

- 611

- 24

I disagree. I always thought that the wave function multiplied by its complex conjugate (that is, [itex]\Psi \Psi^*[/itex]) yielded the probability density for the particle. They are definitely not the same, because [itex]\forall a,b \neq 0, \ (a+bi)^2 = a^2 + 2abi + b^2 \neq a^2 + b^2[/itex].

So, is the probability density given by [itex]\Psi^2[/itex] or [itex]\Psi \Psi^* = |\Psi|^2[/itex]?