Probability: Discrete Random Variable

AI Thread Summary
The discussion revolves around a discrete random variable X with a given probability generating function G(z) = z^2 * exp(4z-4). Participants clarify the distinction between probability generating functions and moment-generating functions, emphasizing that the latter is less convenient for discrete variables. Guidance is provided on how to derive the distribution, expected value, and variance using the moment-generating function. The conversation highlights the importance of understanding the correct function to use for calculations. Overall, the thread serves as a resource for tackling problems related to discrete random variables.
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Homework Statement


Suppose X is a discrete random variable whose probability generating function is
G(z) = z^2 * exp(4z-4)


Homework Equations


No idea


The Attempt at a Solution


I'm thinking that due to the exponent on the z term, that the exp(4z-4) would be the
P[X=3] = exp(4z-4), but I'm not even sure of this.

I honestly have no idea where to even start on a problem like this. Any sort of guidance would be great.
 
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All the info given in [1] is what was given for the problem, I forgot to say that I am suppose to find the expected value, var[x], and the distribution on x.

I honestly have no idea what I am doing. Any hints would be great.
 
Well, that link has the information. Have a look, have a go, and then show us where you get stuck.

Start with m_X(t) = \sum_{k=0}^n {P(X=k) e^{kt}}... to get the distribution, then use the definitions for expectation and variance.
 
Simon Bridge said:
Well, that link has the information. Have a look, have a go, and then show us where you get stuck.

Start with m_X(t) = \sum_{k=0}^n {P(X=k) e^{kt}}... to get the distribution, then use the definitions for expectation and variance.

What you have written is the "moment-generating function", rather that the probability generating function. For a discrete random variable X \in \{0,1,2,\ldots \} the probability generating function is
G(z) \equiv E z^X = \sum_{k=0}^{\infty} P(X=k) z^k.
See, eg., http://en.wikipedia.org/wiki/Probability-generating_function .


RGV
 
What you have written is the "moment-generating function"
Why yes I did, and it is indeed - please see post #2, and the link from that post, for the reasoning behind that :)
 
Simon Bridge said:
Why yes I did, and it is indeed - please see post #2, and the link from that post, for the reasoning behind that :)

Of course one can use the moment-generating function for discrete, integer-valued random variables, but it is not very convenient; the moment-generating function (or Laplace transform) works better for continuous random variables. In the OP's example, the mgf would be
M_X(t) = G(e^t) = e^{2t - 4 + 4e^t},
which is not particularly nice to work with.

RGV
 
Well... either way OP has a place to start.
 
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