Probability Distribution of 4 Balls: Mean & Variance

Click For Summary
SUMMARY

The discussion focuses on calculating the probability distribution, mean, and variance of drawing 4 balls from an urn containing 4 red and 4 white balls. Two sampling methods are considered: "sampling with replacement" and "sampling without replacement." For sampling with replacement, the probability of drawing 0 red balls is 1/16, while for sampling without replacement, the probability of drawing 0 red balls is 1/70. The use of binomial coefficients is essential for determining the probabilities of different outcomes in the sampling process.

PREREQUISITES
  • Understanding of probability distributions
  • Knowledge of binomial probability distribution
  • Familiarity with sampling methods (with and without replacement)
  • Basic statistical concepts of mean and variance
NEXT STEPS
  • Learn how to calculate probabilities using binomial coefficients
  • Study the differences between sampling with and without replacement
  • Explore the application of variance in probability distributions
  • Investigate the implications of different sample sizes on probability outcomes
USEFUL FOR

Students and professionals in statistics, data analysts, and anyone interested in understanding probability distributions and their applications in real-world scenarios.

blumfeld0
Messages
146
Reaction score
0
an urn contains 4 red balls and 4 white balls
an experiment consists of selecting at random a sample of 4 balls and
recording the number of red balls in the sample
setup the probability distribution and compute its mean and variance

i know what a probability distribution is. can someone please how to calculate A probability and i can calculate the rest
also i know mean = total * probability of success = what numbers exactly?

variance = SQRT(total*sucsess * failure) = what numbers exactly?
 
Physics news on Phys.org
Do you know anything about binomial probability distribution ?
 
The first thing we need to know is whether this is "sampling with replacement" or "sampling without replacement". That is, whether a ball, after it is drawn from the urn and its color recorded is or is not returned to the urn.

Obviously, there are 5 possible outcomes: 0, 1, 2, 3, or 4 red balls in the sample.

Assuming "sampling with replacement", the probability of drawing a red ball is 4/8= 1/2 and the probability of drawing a white ball is 1/2 on each draw. In order to get 0 red balls, you have to draw a white ball each time: the probability of that is (1/2)(1/2)(1/2)(1/2)= 1/16. In order to get exactly 1 red ball, you will also need to consider the different orders in which it can be done: "red, white, white, white", "white, red, white, white", etc. That's where the binomial coefficient and the binomial probability distribution arnbg mentioned comes in.

If, on the other hand, this is "sampling without replacement", it's a lot harder! The probability of getting a white ball on the first draw is still 1/2 but IF that happens, there are now 4 red and 3 white balls in the urn. The probability of getting a second white ball is now 3/7. Then there are 4 red and 2 white balls in the urn. The probability of a third white ball is 2/6= 1/3. Finally, there are 4 red and only 1 white ball in the urn. The probability of drawing a fourth white ball is 1/5. The probability of 0 red balls (4 white balls) is (1/2)(3/7)(1/3)(1/5)= 1/70.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
5K
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
9
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
25
Views
5K
  • · Replies 2 ·
Replies
2
Views
1K