Probability Help: Find Probability of Uncracked Egg Carton

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Homework Help Overview

The problem involves calculating the probability of a carton of eggs being uncracked, given the probability of at least one cracked egg is 0.04. The context is within the subject area of probability theory.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between the probabilities of having at least one cracked egg and having none. Questions are raised about which equations or principles apply to this scenario.

Discussion Status

Some participants have provided insights into the relationship between the probabilities, noting that the sum of the probabilities of all possible outcomes must equal 1. There is a recognition of the simplicity of the problem after some clarification.

Contextual Notes

Participants express uncertainty about the appropriate equations to use and the reasoning behind the probability calculations. There is an acknowledgment of the basic principles of probability being relevant to the discussion.

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Homework Statement



The question states: The probability that a carton of eggs has a (at least one) cracked egg is .04. What is the probability that your carton is fine?


Homework Equations





The Attempt at a Solution



I'm not sure how to go about this one. I'm pretty comfortable with the beginning probability stuff, but I'm sure as to which equation applies here. If someone can point me in the right direction I would be so grateful.

Thank you very much.
 
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What is the sum of the probabilities that i) the carton contains at least one cracked egg and ii) the carton contains no cracked eggs?
 
Think about it, if the probability of having AT LEAST 1 is 0.04, what is the probability of having NONE?

For another question with a similar answer that may help you understand what the question is asking:

If the probability of winning a draw is 5%(no ties are possible), what is the probability that you will lose? Well what are the possibilities... You could either win or lose. So if you have a 5% chance of winning, you must have a 95% chance of losing.

edit: As Dick said, the sum of all the possible outcomes is always 1.00 (100%). So p(at least 1) + p(0) = 1, right?
 
Last edited:
That completely makes sense now. I feel kind of stupid now cause it's actually super easy.

Thank you for helping.
 

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