Probability help/sigma-algebras

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Discussion Overview

The discussion revolves around proving that a specific collection of sets, defined as F={A∩E : E is an element of ε}, forms a sigma-algebra on the set A within a probability space (S, ε, P). The focus is on the properties required for F to be a sigma-algebra, including closure under complementation and countable unions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant notes the need to show that A is in F, the complement of A∩E is in F, and that a countable union of sets of the form A∩E_i is in F.
  • Another participant expresses confusion about the direction of the proof, initially thinking F should be contained in A.
  • A participant reiterates that F consists of subsets of A and encourages checking the definition of a sigma-algebra for clarity.

Areas of Agreement / Disagreement

Participants generally agree on the properties that need to be demonstrated for F to be a sigma-algebra, but there is some confusion regarding the correct approach to the proof and the definitions involved.

Contextual Notes

Some participants express uncertainty about how to properly articulate their reasoning and the definitions of sigma-algebras, indicating potential gaps in understanding the foundational concepts.

FTaylor244
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Let (S, ε, P) be a probability space and let A be an element of ε with P(A)>0. Let F={AπE :E is an element of ε }
-Prove that F is a sigma-algebra on A.



Not sure even where to go with this really. I know that to be a sigma-algebra has to be closed under complementation and countable unions. I'm not very good with proofs, and just a push in the right direction would help me out a ton. Thanks!
 
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So you will need to show that:

- A is in F
- The complement of A cap E is in F
- A countable union U_i A cap E_i is in F.

All you need to know are the properties of sets and that epsilon is a sigma algebra. Try it and show what you have tried.
 
Oh, I was under the impression I had to do it the other way around, such that F is in A, etc..maybe that's why I'm having such a hard time here.

Ok so...

A is in F because F=A intersect E, and since an intersect of A is in F, then all of A has to be in F (not sure how to write this properly)
F=AnE is the same as F=(A^c U E^c)^c (^c=complement)
not really sure how to go about the last one
 
FTaylor244 said:
A is in F because F=A intersect E, and since an intersect of A is in F, then all of A has to be in F (not sure how to write this properly)
F=AnE is the same as F=(A^c U E^c)^c (^c=complement)
not really sure how to go about the last one

F is a set of subsets of A, namely the set of A cap E for E in the sigma algebra. Check the definition of a sigma algebra. Try again keeping that in mind.
 

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