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Sigma Algebra on Omega (Sample Space)

  1. Oct 22, 2013 #1
    2ikcc4o.jpg

    Respected Members,

    Suppose Ω is the set of eight possible outcomes of three coin tosses i.e. Ω={{HHH, HHT, HTH, HTTT, THH, THT, TTH, TTT}
    So if we are not told the results then the sigma algebra ( denoted by F_α) at position α=0 is
    F_0 = {∅, Ω}

    Now if are told the first coin toss only then,
    A_H={HHH, HHT, HTH, HTTT}, and A_T={THH, THT, TTH, TTT}
    which the sigma Algebra at α=1 is
    F_1={∅, Ω, A_H, A_T}

    now in the attached picture the proof says that

    A_1, A_2,....., A_n,.... ε ∩_αεI F

    if we just consider two sigma algebras for our convenience to check this lets take the intersection of two above coin toss's sigma algebras i.e. F_0 and F_1

    for I= 0 and 1,

    ∩_αεI F_α = F_0 ∩ F_1 = {∅, Ω} ∩ {∅, Ω, A_H, A_T} = {∅, Ω} ----(BETA)

    the proof says that A_1, A_2,....., A_n,.... ε ∩_αεI F_α , and if we consider A_1 as A_H and A_2 as A_T then why are they not in the intersection of F_0 ∩ F_1 as shown in (BETA) ?

    Thanks in advance.
     
  2. jcsd
  3. Oct 22, 2013 #2
    You have [itex]\mathcal F_0=\{\emptyset,\Omega\}[/itex] and [itex]\mathcal F_1=\{\emptyset,A_H,A_T\Omega\}[/itex]. In particular, since [itex]\mathcal F_0\subseteq \mathcal F_1[/itex], your example has [itex]\mathcal F_0\cap\mathcal F_1=\mathcal F_0[/itex].

    What you need for your hypothesis is [itex]A_i \in \mathcal F_0\cap\mathcal F_1=\mathcal F_0=\{\emptyset,\Omega\}[/itex] for every [itex]i[/itex]. That is, every [itex]A_i[/itex] is either empty or the whole state space; in particular, you can't use [itex]A_i=A_H[/itex] or [itex]A_i=A_T[/itex]. To verify the union, notice that the union is just [itex]\Omega[/itex] if at least one of your [itex]A_i=\Omega[/itex] and [itex]\emptyset[/itex] if (the only other possibility) every [itex]A_i=\emptyset[/itex]. In particular, either way, [itex]\bigcup_i A_i \in \mathcal F_0.[/itex]
     
  4. Oct 22, 2013 #3
    Why not A_i=A_H or A_T ? Lets say, A_1={ø}, A_2={Omega}, A_3=A_H and A_4=A_T then A_1, A_2, A_3, A_4 belongs to intersection_alpha belongs to I F_alpha, here F_alpha is F_0
    After all A_H and A_T are the subsets of Omega, and definition 7 says that algebra is a collection of subsets of Omega.

    Ps. Sorry, I am on train and typing this message on mobile therefore I am unable to add accurate symbols :(
     
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