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## Main Question or Discussion Point

Imagine a simple chocolate bar promotion in which there is a 6 in 1 chance of winning another bar. My question is; If you buy six bars, what is the chances that at least one will be a winner?

- Thread starter Dr Chaos
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Imagine a simple chocolate bar promotion in which there is a 6 in 1 chance of winning another bar. My question is; If you buy six bars, what is the chances that at least one will be a winner?

- #2

CompuChip

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It is simply a binomial distribution, letting X = the number of winners in the 6 that you buy, you want to calculate P(X >= 1 | n = 6, p = 1/6)

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CRGreathouse

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One minus the chance that none are winners.My question is; If you buy six bars, what is the chances that at least one will be a winner?

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6 in 1 chance?Imagine a simple chocolate bar promotion in which there is a 6 in 1 chance of winning another bar. My question is; If you buy six bars, what is the chances that at least one will be a winner?

I guess you mean 1 in 6 chance.

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0.665102023319615912208504801098..........

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