Jfontenot06 Messages 2 Reaction score 0 Thread starter May 9, 2006 #1 If you have five coins and you flip them what is the probability that at least one coin falls heads?
siddharth Homework Helper Gold Member Messages 1,145 Reaction score 0 May 9, 2006 #2 Well, what are your thoughts about the problem? Do you have any idea on how you can solve this? You need to show your work before you get help.
Well, what are your thoughts about the problem? Do you have any idea on how you can solve this? You need to show your work before you get help.
mathman Science Advisor Homework Helper Messages 8,130 Reaction score 575 May 9, 2006 #3 Hint: prob at least 1 head = 1 - prob no heads. Try working from there.
Jfontenot06 Messages 2 Reaction score 0 May 9, 2006 #4 Well what I was thinking is that the chances of a coin landing on heads is 1/2. Since there are five coins it should be (1/2)^5 = 1/32
Well what I was thinking is that the chances of a coin landing on heads is 1/2. Since there are five coins it should be (1/2)^5 = 1/32
mattmns Messages 1,129 Reaction score 5 May 9, 2006 #5 That would be the probability of all 5 coins landing on heads. Look back at mathman's hint again, that is where you want to go with the problem.
That would be the probability of all 5 coins landing on heads. Look back at mathman's hint again, that is where you want to go with the problem.
DaveC426913 Gold Member 2025 Award Messages 24,697 Reaction score 9,101 May 10, 2006 #6 Same hint, different angle: What are the chances of throwing a set and having NONE turn up heads?
jimmydelgado777 Messages 2 Reaction score 0 May 19, 2006 #7 For one coin: 3 tosses 2 x 2 x 2 1st toss = happens 2 ways 2nd toss = happens 2 ways 3rd toss = happens 2 ways s = { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} Feel free to correct this. Cheers
For one coin: 3 tosses 2 x 2 x 2 1st toss = happens 2 ways 2nd toss = happens 2 ways 3rd toss = happens 2 ways s = { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} Feel free to correct this. Cheers