Probability of drawing a white ball after successive transfers

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SUMMARY

The discussion focuses on calculating the probability of drawing a white ball from a series of jars after successive transfers. The probability of transferring a white ball from jar k-1 to jar k is defined by the equations $$ P(W_{k}|W_{k-1})= \frac{m+1}{m+n+1} $$ and $$ P(W_{k}|W_{k-1}^{c})=\frac{m}{m+n+1} $$, where m represents the number of white balls and n the number of black balls. The overall probability $$ P(W_{k}) $$ is derived from these conditional probabilities, leading to the equation $$ P(W_{k})=\frac{m}{m+n+1}+\frac{P(W_{k-1})}{m+n+1} $$, which can be used to determine $$ P(W_{k-1}) $$ through recursive calculation.

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Homework Statement
Each of k jars contains m white and n black balls. A ball is randomly chosen from jar 1 and transferred to jar 2 then a ball is randomly chosen from jar 2 and transferred to jar 3,etc. Finally a ball is randomly chosen from jar k. Show that the probability that the last ball is white is the same as the probability that the firs ball is white.
Relevant Equations
Total probability law
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$$ P(\text{The event that the randomly chosen ball from jar 1 is white which is transferred to jar 2})=\frac{m}{m+n} $$
For the last transfer there are two disjoint events:

Conditioned on the event that the ball transferred from jar k-1 to jar k is white the probability that the randomly chosen ball from jar k is white is $$ P(W_{k}|W_{k-1})= \frac{m+1}{m+n+1} $$.

Conditioned on the event that the ball transferred from jar k-1 to jar k is black the probability that the randomly chosen ball from jar k is white is $$ P(W_{k}|W_{k-1}^{c})=\frac{m}{m+n+1} $$.

$$ P(W_{k})=P(W_{k}|W_{k-1})P(W_{k-1})+P(W_{k}|W_{k-1}^{c})P(W_{k-1}^{c})=\frac{m+1}{m+n+1}P(W_{k-1})+\frac{m}{m+n+1}(1-P(W_{k-1}))=\frac{m}{m+n+1}+\frac{P(W_{k-1})}{m+n+1} $$

How can I determine $$ P(W_{k-1}) $$?
 
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