Probability of finding an electron

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SUMMARY

The probability of finding an electron in a specific point, such as on the z-axis, is definitively zero due to the nature of the electron wave function, which is spread over a volume. The discussion confirms that for any finite volume, there is a non-zero probability of locating the electron, but for a point with no volume, the probability is zero. This principle applies universally to random variables with continuous distributions, where the probability of attaining a specific value is always zero.

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  • Understanding of quantum mechanics principles
  • Familiarity with electron wave functions
  • Knowledge of probability theory in continuous distributions
  • Basic grasp of mathematical notation in physics
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  • Learn about probability density functions and their applications
  • Explore the implications of the Heisenberg uncertainty principle
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Let us assume that we have an electron belonging to the px orbital. In that case what would be the probability of finding it on the z axis? Would it be zero? My teacher says so, but I think that because we can't predict the boundary where there is 100% possibility of finding an electron, we can't find a point where the probability of finding it is 0. Who is correct?
 
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You instructor is correct if I understand your question. The electron wave function is spread over a volume. Any finite volume the electron will have some chance of being found there. [edit: the smaller the volume the smaller the probability] The z-axis has no volume so the probability is zero.
 
Paul Colby said:
You instructor is correct if I understand your question. The electron wave function is spread over a volume. Any finite volume the electron will have some chance of being found there. [edit: the smaller the volume the smaller the probability] The z-axis has no volume so the probability is zero.
Does that mean that the probability of finding the electron on the x-axis is 0 too, as it has no volume like the Z axis?
 
Yes, written out ##P_{\Delta V}=\int\int\int_{\Delta V} \vert \psi(x)\vert^2 d^3x## if ##\Delta V=0## then ##P=0##.
 
This discussion is a special case of an obvious principle. The probability of a random variable, with a continuous distribution, having a specific value, is 0.
 

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