Why is the probability of finding an electron of s orbital in the nucleus highest? Is Quantum Tunneling involved? If so, won't the electron need a large amount of energy to pass through the nucleus?
One type of wave function has the highest probability, and that type is called "s" for historical reasons. It has nothing to do with tunneling.Why is the probability of finding an electron of s orbital in the nucleus highest?
That doesn't exactly answer my questions...my questions in are:One type of wave function has the highest probability, and that type is called "s" for historical reasons. It has nothing to do with tunneling.
Neither the electron nor the nucleus are billiard balls, they don't "collide" as classical objects would do. The electron does not need any energy to be (partially) in the nucleus, and it does not "pass" the nucleus.
By symmetry (spherical symmetry of the potential), it has to reach a maximum or a minimum. All wave functions with a maximum there are called "s".-Why is the amplitude of wave function reach an antinode at the nucleus, making the probability density highest at the nucleus?
Yes, it is equivalent to that.-Does it have anything to do with angular momentum being zero?
The electron "is" everywhere in its wave function "at the same time" - only a (very small) part of the wave function is in the nucleus.-The probability density graphs of s orbitals show a highest density at the center of nucleus- so wouldn't an electron have to be fully in the nucleus? (-Thats probably why I got the weird idea of tunneling; mixed it up with penetration. ) Or is it just a schrodinger's cat scenario?
In principle, this is possible. I don't know how an experimental realization of that would look like.-Can an electron be 'detected' experimentally at the nucleus? (ie.Collapsing the wave form and fixing position at nucleus)
Two interpretations can again be given to the P1 curve. An experiment designed to detect the position of the electron with an uncertainty much less than the diameter of the atom itself (using light of short wavelength) will, if repeated a large number of times, result in Fig. 3-4 for P1. That is, the electron will be detected close to the nucleus most frequently and the probability of observing it at some distance from the nucleus will decrease rapidly with increasing r. The atom will be ionized in making each of these observations because the energy of the photons with a wavelength much less than 10-8 cm will be greater than K, the amount of energy required to ionize the hydrogen atom. If light with a wavelength comparable to the diameter of the atom is employed in the experiment, then the electron will not be excited but our knowledge of its position will be correspondingly less precise. In these experiments, in which the electron's energy is not changed, the electron will appear to be "smeared out" and we may interpret P1 as giving the fraction of the total electronic charge to be found in every small volume element of space. (Recall that the addition of the value of Pn for every small volume element over all space adds up to unity, i.e., one electron and one electronic charge.)