Probability of Sample Mean for Poisson Distribution

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SUMMARY

The probability of the sample mean number of snails in a rectangular field, modeled by a Poisson distribution with a mean of 2.25 snails per m², is calculated using the Central Limit Theorem. A random sample of 120 squares yields a sample mean distribution of X ~ N(2.25, 0.01875). The probability that the sample mean is at most 2.5 is determined to be approximately 0.9682, confirming the validity of applying the normal approximation to the Poisson distribution in this context.

PREREQUISITES
  • Understanding of Poisson distribution and its properties
  • Knowledge of the Central Limit Theorem
  • Familiarity with normal distribution and z-scores
  • Basic statistical sampling techniques
NEXT STEPS
  • Study the application of the Central Limit Theorem in different distributions
  • Learn how to calculate probabilities using z-scores in normal distributions
  • Explore advanced topics in Poisson processes and their applications
  • Investigate statistical software tools for performing probability calculations
USEFUL FOR

Students in statistics, data analysts, and researchers working with Poisson distributions and sampling methods will benefit from this discussion.

Unusualskill
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Homework Statement



A rectangular field is gridded into squares of side 1m. at one time of the year the number of snails in the field can be modeled by a Poisson distribution with mean 2.25 per m^2.
(i) a random sample of 120 squares is observed and the number of snails in each square counted. find the probability that the sample mean number of snails is at most 2.5

Homework Equations


using central limit theorem, sample mean of X ~N (2.25, 2.25x1/120=0.01875)

p(sample mean of x<=2.5)
=p(z<(2.5+1/240-2.25)/ √0.01875)
=p(z<1.856)
=09682


The Attempt at a Solution


Is this correct? any1? becuz I am nt sure whether poisson can do this way onot in sampling
 
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Unusualskill said:

Homework Statement



A rectangular field is gridded into squares of side 1m. at one time of the year the number of snails in the field can be modeled by a Poisson distribution with mean 2.25 per m^2.
(i) a random sample of 120 squares is observed and the number of snails in each square counted. find the probability that the sample mean number of snails is at most 2.5

Homework Equations


using central limit theorem, sample mean of X ~N (2.25, 2.25x1/120=0.01875)

p(sample mean of x<=2.5)
=p(z<(2.5+1/240-2.25)/ √0.01875)
=p(z<1.856)
=09682


The Attempt at a Solution


Is this correct? any1? becuz I am nt sure whether poisson can do this way onot in sampling

Please write proper english here; any1 = anyone, I am = I'm, etc, etc. After you fix that up I will be glad to tell you whether or not I agree with your solution.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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