Probability of soft-drink machine

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SUMMARY

The discussion focuses on calculating the probability of a soft-drink machine dispensing between 191 ml and 209 ml per cup, given a mean of 200 ml and a standard deviation of 15 ml. The initial calculations using Z-scores resulted in a probability of 0.4714, but the correct probability, as referenced from the book "Areas under the normal curve," is 0.4514. The participant questions the necessity of continuity corrections in this context, concluding that they are not required unless specified for discrete amounts.

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A soft-drink machine discharges an average of 200 ml per cup, with a standard deviation of 15 ml. What is the probability that a cup contains between 191 and 209 ml?


Attempt:

Z_1 = \frac{190.5-200}{15} = -0.63

Z_2 = \frac{209.5-200}{15} = 0.63

The table in my book "Areas under the normal curve", gives P = 0.7357-0.2643 = 0.4714

Correct answer (according to the same book): 0.4514

Are my continuity corrections wrong?
 
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I don't think that you need a continuity correction here, unless the problem specifies that the machine can only dispense discrete amounts.

(209 - 200)/15 = .6

P(Z < .6) = .7257
.7257 - (1-.7257) = .4514
 

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