Probability of Spin in Y-up direction

Click For Summary
SUMMARY

The discussion focuses on calculating the probability of a spin-1/2 particle being in the up spin state along the y-direction when initially in the up spin state along the z-direction. The relevant equations include the transformation of spin states between the z and y bases, specifically equations for YUP and YDOWN in terms of ZUP and ZDOWN. The user seeks to rewrite these equations to facilitate the calculation of probabilities using the cosine and sine functions derived from the state vector. The approach is confirmed as correct, with suggestions to simplify the problem further.

PREREQUISITES
  • Understanding of quantum mechanics, specifically spin-1/2 particles
  • Familiarity with state vector notation and transformations
  • Knowledge of probability calculations in quantum states
  • Proficiency in using trigonometric identities in quantum mechanics
NEXT STEPS
  • Study the derivation of spin state transformations in quantum mechanics
  • Learn about expectation values for quantum operators, particularly for spin-1/2 systems
  • Explore the implications of measurement in quantum mechanics, focusing on the collapse of the wave function
  • Investigate the use of Bloch spheres to visualize spin states and their transformations
USEFUL FOR

Students of quantum mechanics, physicists working with spin systems, and anyone interested in the mathematical foundations of quantum state measurements.

Raynor49
Messages
10
Reaction score
0

Homework Statement


a) If a spin-1/2 particle is in the up spin state along z, what is the probability that if its spin along the y-direction is measured it will be found to be pointing in the “up” direction along y?

(b) Calculate the expectation values of the components of S, i.e. {Sx, Sy, Sz}, for a spin-1/2 particle in the state χ+z , i.e. spin-up along z

(c) Ditto in the state χ-z, i.e. spin-down along z.

Homework Equations


1) ψ ( θ) = cos(θ/2)ZUP + sin(θ/2)ZDOWN.
2) YUP = (ZUP + iZDOWN)/√2
3) YDOWN = (ZUP − iZDOWN)/√2

The Attempt at a Solution


For a), can you rewrite equations 2 and 3 like ZUP = (YUP + iYDOWN)/√2 & ZDOWN = (YUP − iYDOWN)/√2 to plug into equation 1? Since I know from equation 1 the probabilities of zup or zdown are (cos(θ/2))^2 & (sin(θ/2))^2 respectively, if you subbed in the y values for zup and zdown, could you then simplify and square the coefficients of yup and ydown to get their probabilities?

Any help is appreciated! Thanks!
 
Physics news on Phys.org
Your approach is correct, but I don't see what you're going to do with equation 1. Can't you simplify the problem further?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
3K