MHB Probability of Winning in Poker with Three Jacks and Two High Cards - Week #79

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In a poker hand with three jacks and two high cards, the probability of an opponent having a higher three of a kind, specifically three queens, kings, or aces, is calculated based on the remaining cards in the deck. Given that there are only four of each rank in a standard deck, the likelihood of drawing three of a kind from the higher ranks is limited by the cards already dealt. The discussion reveals that no participants arrived at a correct solution for this scenario. Understanding the combinatorial aspects of poker hands is crucial for determining these probabilities. The complexity of the situation highlights the challenges in calculating poker odds accurately.
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You are playing some poker with a friend. Say you are dealt 5 cards from a 52 card deck and have three jacks plus the 2 of diamonds and the 5 of hearts. What is the probability that your friend has a higher 3 of a kind, that is three Q's, K's or A's?
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There were no correct solutions this week. :(

Solution:
5 cards from the 52 are already accounted for thus our hand is chosen from a pile of 47 cards. For each situation - 3 Kings, Queens or Aces - they all have the same probability so we can find one of them and multiply by 3.

There are 4 Queens from which to choose 3 and 43 cards left over from which to choose the other 2 cards. However these last two cards also cannot be the same, so for the first card we have 43 choices and for the second card we have 39 choices.

$$P[\text{3 Queens}]=\frac{\binom{4}{3} \left(\frac{43 \times 39}{2!}\right)}{\binom{47}{5}} \approx 0.0021865$$

$$P[\text{3 Queens}] \times 3 = \boxed{0.00656}$$
 
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