Probability of Winning Tickets in a Box with 80 Tickets and 10 People

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SUMMARY

The probability of winning tickets in a scenario with 80 tickets and 10 people, each purchasing 10 tickets, involves calculating specific outcomes based on combinatorial mathematics. The first calculation shows that the probability of one person winning all 3 winning tickets is determined using the formula 10 C 3 * 70 C 7 divided by 80 C 10. The discussion also explores scenarios involving multiple winners, emphasizing the need for precise combinatorial analysis to derive accurate probabilities.

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  • Understanding of binomial coefficients (C notation)
  • Basic probability theory
  • Familiarity with ticket distribution scenarios
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  • Explore advanced probability scenarios involving multiple outcomes
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Bachelier
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In a box with 80 tickets, 10 people buy 10 tickets each. If there are 4 winning tickets drawn at random find the probability that
1) one person gets all 3 winning tickets
2) there are 3 different winners
3) some person gets two winners and someone else gets just one

for 1) 10 C 3 * 70 C 7

is the answer = -------------------- where C stands for chooses.
80 C 10

Thnks
 
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Bachelier said:
In a box with 80 tickets, 10 people buy 10 tickets each.

That's 100 tickets :redface: …

have the police been informed?​
 

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