Probability problem - finding standard deviation and mean in a normal dist.

Click For Summary
The discussion centers on a probability problem involving the normal distribution of heart rate increases during exercise. The mean heart rate increase is 40 bpm with a standard deviation of 9 bpm, and the study identifies 15% of participants as unfit (heart rates ≥ 50 bpm) and 10% as very fit (heart rates ≤ 22 bpm). The original poster initially struggled with the problem but later solved it by calculating z-scores for the specified percentages and applying the formula z = (x - mu)/sigma. This approach led to the formulation of simultaneous equations that were straightforward to solve. The poster shared their solution for future reference, contributing to the community's understanding of similar problems.
Hamish Cruickshank
Messages
5
Reaction score
0
Hey all.

Im doing maths methods 5 (i live in Australia) and I've run into this problem.
Code:
A university study investigated the increase in 
heart rates(measured in beats per minute) of 
people undertaking a particular exercise. The 
increases in heart rate were normally distributed 
with a mean of 40 and a standard deviation of 9.

It was determined that the proportion of people 
classified as unfit (x >= 50) is 15% and the 
proportion of people classified as very fit (x <= 22) is 10%. 
Find the mean and standard deviation of the increases 
in heart rate for this university study.

I've no idea how to do this.

Most of these types of problems I have been doing on a graphics calculator, which is allowed and expected in this course. The model of calculator I have is a CASIO fx-9860G AU.

Any help in solving this problem will be greatly appreciated.

Thanks for reading.
 
Physics news on Phys.org
Its okay, I got it figured out.

I took the z scores for those percentages as if they were standard normal distributions and then substituted them into the formula z = (x - mu)/sigma. I then had simultaneous equations which were quite easy to solve. I thought i'd answer my own question for anyone who wanted future reference.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
11K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
4K
  • · Replies 7 ·
Replies
7
Views
8K