Probability solved with expected value E(X)

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SUMMARY

The discussion centers on calculating the expected value E(X) for a multiple-choice test question with 6 possible answers, where only one answer is correct. The correct answer awards 10 points, while the goal is to determine the penalty for a wrong answer that results in an average score of 0 points when answers are chosen randomly. The correct formula for expected value is E(X) = 10*(1/6) + x*(5/6) = 0, where x represents the points deducted for a wrong answer. Solving this equation reveals that x must equal -12 points.

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  • Understanding of expected value in probability theory
  • Basic knowledge of multiple-choice test scoring systems
  • Familiarity with algebraic equations and solving for unknowns
  • Concept of probability distribution for discrete outcomes
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  • Learn about probability distributions and their applications
  • Explore scoring systems for standardized tests
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Students, educators, and test designers interested in understanding probability and scoring mechanisms in multiple-choice assessments.

ParisSpart
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A question on a multiple choice test has 6 answers which just one is right and the other wrong.

If the amount of the correct answer is 10 points how many points should be substracted for a wrong answer so if nobody answers randomly choosing one of the 6 answers get, on average, 0 points?



i thinh that this problem can be solved with expected value E(X) but i am confused on how to do it
maybe this E(X)=10*(1/6)+0*(1/6)?
 
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Your "E(X)= 10*(1/6)+ 0(1/6) is almost right but: you have "0" right where you want your unknown- the number of points given for a wrong answer and the probability of a wrong answer is 5/6, not 1/6. And you want the expected value to be 0: 10(1/6)+ x(5/6)= 0. Solve that for x.
 

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