Probability when rolling 6 true dice

[doublemint]

Hello,

So the question is: You have 6 true dice and you want to find the probability of rolling exactly two aces (im assumming ace means 1).
I tried using the binomial theroem:
P = (6!/(2!4!)) (1/6)^2 (5/6)^4 = 0.2009
But the answer is 0.040..So where did I go wrong?

Thanks
DoubleMint

 

[Ray Vickson]

Your answer is correct; you did nothing wrong.

RGV