Probability. You roll, I roll game.

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Homework Help Overview

The problem involves rolling dice in a game where one player wins if their die shows a strictly greater number than the other player's die. The question asks for the probability of winning at least four out of five games played. The context is centered around probability and binomial distributions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss their understanding of the game setup and the interpretation of the rules, particularly regarding the number of games played and the conditions for winning. Some express confusion about the wording and the implications of the game structure.

Discussion Status

There are various interpretations of the problem being explored, with some participants attempting to clarify their understanding of the game mechanics. A few have suggested using the binomial theorem to approach the problem, while others are still grappling with the wording and implications of the game rules.

Contextual Notes

Some participants note ambiguity in the wording of the problem, particularly regarding the conditions under which a player wins and how the games are structured. This has led to differing interpretations of the probability calculations involved.

bizboy1
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Homework Statement


You roll a die, and I roll a die. You win if the number showing on your die is strictly greater than the one on mine. If we play this game five times, what is the chance that you win at least four times? The answer is .1005

2. Related Equations[\b]
Binomial

The Attempt at a Solution


I haven't got anywhere.
I know the game looks something like this:
ffs
fffs
ffffs
fffffs
blacks

and I found all 15 pairs to win. I'm just not sure how I should think about it. This is not for homework. I am reviewing probability. Thanks!
 
Last edited:
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I think I figured it out. The problem with me and these questions is that I read them wrong/differently. Anyone else confused by the five games?
 
Try warming up by finding the probability if the game is played only once.
 
I got it. The trick was applying the binomial theorem to the wins and not to the individual rolls.
 
bizboy1 said:
I think I figured it out. The problem with me and these questions is that I read them wrong/differently. Anyone else confused by the five games?

I was confused by trying to respond to this problem and trying to figure out what to do with "I" and "you". The five games part wasn't particularly confusing.
 
Answer: Probability of a win is 15/36. Now then use binomial(5,4)*(15/36)^4*(21/36)+binomial(5,5)*(15/36)^5
 
My confusion was the word play. Play means exactly what? 5 rolls total? That doesn't make sense. So it must be 5 complete games. Game includes the complete description.
 
bizboy1 said:
Answer: Probability of a win is 15/36. Now then use binomial(5,4)*(15/36)^4*(21/36)+binomial(5,5)*(15/36)^5

Sure it is.
 
bizboy1 said:

Homework Statement


You roll a die, and I roll a die. You win if the number showing on your die is strictly greater than the one on mine. If we play this game five times, what is the chance that you win at least four times? The answer is .1005

2. Related Equations[\b]
Binomial

The Attempt at a Solution


I haven't got anywhere.
I know the game looks something like this:
ffs
fffs
ffffs
fffffs
blacks

and I found all 15 pairs to win. I'm just not sure how I should think about it. This is not for homework. I am reviewing probability. Thanks!


The wording is ambiguous: you say "You win if the number showing on your die is strictly greater than the one on mine". Does that mean that I win if my number is >= yours? (Another interpretation would be: you win if your number is larger, I win if my number is larger and we toss again if both numbers are equal. In that case, we each have a 1/2 chance to win in each play of the game---where 1 play means we keep tossing until someone wins.)

RGV
 

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