Problem 7.46: Riding a Loop-the-loop

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To determine the minimum height for a car to complete a loop-the-loop without falling off, it is established that the height must be at least 4 times the radius of the loop. Given a radius of 25.0, this translates to a minimum starting height of 100.0. The speed of the passengers at the end of the horizontal diameter is calculated using the energy conservation equation, resulting in a speed of approximately 14.1 m/s. The calculations utilize the principles of gravitational potential energy and kinetic energy. Overall, the discussion emphasizes the importance of height and energy conservation in amusement park ride dynamics.
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Homework Statement



A car in an amusement park ride rolls without friction around the track shown in the figure . It starts from rest at point at a height above the bottom of the loop. Treat the car as a particle.

What is the minimum value of (in terms of ) such that the car moves around the loop without falling off at the top (point )?

If the car starts at height 4.00 and the radius is = 25.0 , compute the speed of the passengers when the car is at point , which is at the end of a horizontal diameter.

Homework Equations



mgh = 1/2 mv^2

The Attempt at a Solution



we know that h = 2 R because it's the diameter but other than that i am lost
 
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. For the minimum value, I believe it is 4R. For the speed, we use the equation mgh = 1/2 mv^2. mgh = 1/2 mv^2(4)(9.8)(25) = 1/2 (20)(v^2)1960 = 10v^2196 = v^214.1 m/s = v
 
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