Problem about equivalent conditions for a basis of a free module

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SUMMARY

The discussion centers on the conditions for a basis of a free module, specifically addressing the implications between various statements labeled a, b, c, and d. The user demonstrates that if a basis exists (statement a), then there are finitely many nonzero elements in the generating set (statement b) due to the properties of the basis. The user successfully proves that b implies d and c, while also establishing the uniqueness of the elements under the assumption of finitely many nonzero elements in b.

PREREQUISITES
  • Understanding of free modules in abstract algebra
  • Familiarity with the concept of bases in vector spaces
  • Knowledge of implications in mathematical logic
  • Basic proficiency in notation used in algebraic structures
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  • Study the properties of free modules in depth
  • Explore the implications of bases in vector spaces
  • Learn about generating sets and their significance in module theory
  • Investigate uniqueness proofs in algebraic contexts
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Mathematicians, algebra students, and educators interested in module theory and the foundational aspects of abstract algebra.

Ganitadnya
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Here's the problem:
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I don't see why there should be only finitely many nonzero a_z in b. I was able to prove uniqueness assuming that there only finitely many nonzero. I was able to show b implies d and b implies c, c implies a.
 

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So you're referring to the implication (a) $\implies$ (b). There are only finitely many $a_z$ in (b) simply because $Z$ is a generating set for $M$ (since it is a basis by (a)).
 

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