- #1
agnibho
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Homework Statement
ABCD is a parallelogram. E, F are points on the straight line parallel to AB. AF, BF meet at P, and DE, CF meet at Q. Prove that PQ ll AD.
2. The attempt at a solution
I drew the diagram.
I tried to solve the problem in this way:-
CD ll XY Therefore, angleCDE = angleDEF (alternate interior angles)
Also, angleDCF = angleCFE (alt. int. angles)
Hence, triangle DQC is similar to triangle FQE
So, DQ/QE = CQ/QF
After this I felt at a loss. I couldn't figure out the next step. I thought that if I could anyhow prove that the angleEQP = angleEDA, then I could've said that they are equal but they are corresponding angles and hence I could've proved PQ ll AD.
Someone please help me with the next step .