Problem involving set and relations

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The discussion focuses on proving that if relation R is a subset of relation S on set A, then R raised to the power of n (R^n) is also a subset of S raised to the power of n (S^n) for all n ≥ 1. The user attempted a proof by induction, establishing the base case for n=1 and moving to the inductive step. The user sought clarification on how to proceed with the proof, specifically needing guidance on the relationship between elements of R^n+1 and R.

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First this is my first attempt at using latex to ask a question, so my appologies if the statements come out strange. I'll edit as needed.

Homework Statement


Let R and S be relations on a set A. Prove that if R \subseteq S, then R^{n} \subseteq S^{n} for all n \geq 1


Homework Equations


n/a


The Attempt at a Solution


I used proof by induction.

Base case:
Let n=1 thenR \subseteq S, thenR^{n} \subseteq S^{n} =R^{1} \subseteq S^{1} which is equal to R \subseteq Swhich is true.

Inductive step:
Suppose that R^{k} \subseteq S^{k}forn=kand [/tex]k \geq 1[\tex]
We need to show that R^{k+1} \subseteq S^{k+1}is true as well.
R^{k+1} \subseteq S^{k+1} = R \circ R^{k} \subseteq S \circ S^{k}

ok, so here goes. I'm lost at this point. I know that for instance, if (a,b) are elements of Rn then it must be the case that (a,b) are elements of Sn

Any help, prefferably hints as I'd rather learn then get complete solutions handed to me would be greatly appreciated.
Thanks for reading
 
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hi nistaria! :smile:

your induction proof needs to begin "if (a,b) ε Rn+1, then there is a c such that …" :wink:
 

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