Two skaters on a frictionless pond push apart from one another. One skater has mass M much greater than the mass m of the second skater. After some time the two skaters are a distance d apart. How far has the lighter moved from original position.
The answer is somehow d((M)/(M+m))
conservation of momentum, delta x = v*time
The Attempt at a Solution
I understand the two skaters have equal but opposite momentum after they push each other.
so M*v1 = m*v2
and the position of is given by x2 = v2*t = M/m*v1
d = x2 - x1
.... whenever I try to substitute for v2*t, I get an answer of d...
I just can't seem to get the solution they get...