Capacitor Problem: Charge, Electric Displacement, and Current Calculations

  • Thread starter Thread starter TPDC130
  • Start date Start date
  • Tags Tags
    Capacitors
Click For Summary
The discussion revolves around calculating charge, electric displacement current, and wire current in a parallel plate capacitor subjected to an electric potential of Vo*sin(wt). The charge on the plates is determined as Q = C*Vo*sin(wt), while the electric displacement current is calculated as I = ε*w*cos(wt). The current in the wire is found to be i = C*w*cos(wt). There is a concern about the simplicity of these answers and a query regarding the difference between the displacement current and the current in the wire. The conversation emphasizes the need for clarity in understanding these concepts.
TPDC130
Messages
6
Reaction score
0

Homework Statement


Given an electric potential of Vo*sin(wt). This is applied to a parallel plate capacitor of area S, separation d and capacitance C. The questions are
a) What is charge Q on the plates?
b) Find the electric displacement current
c) Calculate the current in the wire.


Homework Equations


a) Q=CV
b) I=(epsilon)*d(phi)/dt
c) i=dQ/dt

The Attempt at a Solution



for part a, i got Q=CV=C*Vo*sin(wt)
for part b, i got I=(epsilon)*w*cos(wt)
for part c, i got i=C*w*cos(wt)


is this right, because i have a feeling that this is a little too easy of an answer.
why does the displacement current differ from the current in the wire?
 
Physics news on Phys.org
Rewrite that with \LaTeX code,I think it`s easy as it can be.

It`s pain to read like that.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
632
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
19
Views
3K
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
2
Views
2K